Chapter 15
Problem
After attending Gina’s
birthday party, Sonia’s mom asked Sonia what she saw at Gina’s house. Sonia
said that there are some chickens and rabbits in Gina’s backyard. Mom asked
Sonia how many chickens there are and how many rabbits there are. Sonia forgot
the number of chickens and rabbits, but she remembered that there were 9 heads
and 28 feet. How can Mom help Sonia to find out how many chickens and rabbits
there are?
This is the way I learned to solve the problem:
The number of rabbits: (28 – 9 x 2) ¸ 2 = 5
The number of chickens: 9 – 5 = 4
179
The
above method and answer are both correct. But even if the expression, (28 – 9 x
2) ¸ 2, is broken down into three separate steps
(as below), it is still hard for students to understand.
To find the number of rabbits:
1st
step: 9 x 2 = 18
2nd
step: 28 – 18 = 10
3rd
step: 10 ¸ 2 = 5 (rabbits)
To find the number of
chickens:
4th
step: 9 – 5 = 4 (chickens)
The problem is not an easy
problem for 4th, 5th, or 6th graders to solve.
So I asked myself, “Can I teach my 5 year old daughter, Gina, to solve it,
because it is an interesting problem?”
The method I learned was correct, as noted above. But the problem was too hard to understand when I was 8. The problem has only two clues. The first clue is 9 heads. The second clue is 28 feet. The problem didn’t tell me how many chicken heads, rabbit heads, chicken feet or rabbit feet there were. That made the problem more challenging.
To solve the problem, we must know that a rabbit has four feet and a chicken has two feet. Based on that knowledge and our clues, let’s evaluate the three steps that I learned. I will explain the procedure in detail.
In the 1st step,
since each animal has at least two feet, we can write 9 x 2 (9 being the total
number of animals, since each animal obviously has one head).
In the 2nd step,
since a chicken has two feet, the remaining feet are rabbits’ feet. To find the
number of remaining feet, we solve 28 – 9 x 2. The result is 10.
In the 3rd step,
since each rabbit has two feet not yet accounted for, we divide the remaining
feet by 2, to obtain the number of rabbits. We can write (28 – 9 x 2) ¸ 2, or 10 ¸ 2. The result is 5.
In the 4th step,
since we know the number of rabbits and the total number of animals, the number
of chickens is 9 – 5, which equals 4.
After reading my
explanation, how do you feel? Is it complicated to you, an adult? Do you think
that 3rd, 4th, 5th, or 6th graders
will be able to understand the method? Because it is a very challenging problem
to many adults, it may be too challenging for 3rd to 6th
grade students. Is there a more child-appropriate way to solve this problem?
Of course, there is always more than one way to solve any problem, but our goal is to find a method useful at the elementary school level. I think that I found the best way to teach this problem six years ago.
When people ask me how I found a Child-learning Method to solve this problem, my answer is two words: “by heart.” And this is a lesson to all parents: as an outgrowth of your love for your child, you should challenge yourself to teach your child as much as you can, and find creative ways to teach abstract concepts.
To teach my 5 year-old daughter, I developed a six-step method to solve the problem, one that is easier (that is, more child-appropriate) than the adult-oriented method above.
1st step: I asked
Gina to draw 9 circles, since there are 9 heads (animals). Each circle
represents a head.

2nd step: I asked
Gina to draw two “feet” on each circle, since each animal has at least two
feet.

3rd
step: I asked her to count the number of feet she drew. Since she drew two feet
for each head, she told me that she used 18 feet (that is, 9 x 2 = 18).

4th step: I asked
her how many feet remained. She answered that there were 10 feet left (that is,
28 – 18 = 10).

5th step: This is
a very interesting part. I asked Gina whose feet are the remaining feet. She
thought about it for a second and told me, “The remaining feet belong to rabbits.”

I continued to question her, to see if she could distribute the remaining feet to rabbits. Guess what her response was? Instead of answering my question, she asked me which of the heads were rabbits’.
I thought that I should give her a hint. “Can we assume that any of the heads could be rabbits’ heads?” I was surprised when she said yes. I realized that we must be very careful not to miss small detail links while teaching.

After she drew two feet on one of the heads, I asked her what she should do next. She said that she should draw feet on more heads.

I asked her how many more feet she needed to draw. She said that she needed to draw 8 more feet. (I was thinking to myself, “How would I answer her if she said, ‘I don’t know’?” I probably would have given her a hint, such as, “How many feet are remaining?”) She drew 8 feet, two each on four of the remaining heads.

6th step: I asked
Gina to count how many heads have four feet and asked what type of animal that
is. She counted and told me, “There are 5 heads with 4 feet and they are
rabbits.” Then I asked her how many chickens there are. She answered, “4
chickens.” What would I have done, if she hadn’t known what type of animal had
4 feet? I would have given her a hint by asking, “Which animal has 4 feet?”
Let’s compare the way that I learned and the way that Gina learned. It should be easy to tell which is the Child-learning Method.
The way I learned, at age 8, not fully comprehending:
1st
step: 9 x 2 = 18
2nd step: 28 – 18 = 10
3rd
step: 10 ¸ 2 = 5 (rabbits)
4th
step: 9 – 5 = 4 (chickens)
The way Gina learned, at age 5, with full comprehension:
1st step: Draw 9
circles to represent 9 heads.
2nd step: Draw
two feet on each circle.
3rd step: Count how many feet have been on the
circles: 9 x 2 = 18
4th step: Find
the remaining feet. 28 – 18 = 10
5th step:
Distribute the remaining feet on some of the
circles (two feet per circle): 10 ¸ 2 = 5
6th step: Count how
many heads have 4 feet, (the
rabbits), and how many heads have 2 feet (the
chickens).
A very complicated problem is solved using a method that a child of 5 can understand. Isn’t it wonderful to have a method that reaches the elementary school-age child? Isn’t it fun to challenge ourselves?
Questions to Ask Ourselves: the diagnostic list of questions below will provide
us with direction to help our students or children to solve the word problems.
(1)
Do
we give them problems that are interesting and appropriate for the age group we
are teaching?
(2)
Do
they like the problems?
(3)
Why
do they like (or not like) the problems?
(4)
Does
the problem challenge them?
(5)
Why
are the problems challenging?
(6)
Do
they have difficulty solving the problems?
(7)
Why
do they have difficulty solving the word problems?
(8)
What
types of word problems do they have trouble with?
(9)
Why
are certain types of word problems difficult for them to solve?
(10)
Do
they understand the problems?
(11)
What
strategy do they use to solve the problem?
(12)
Do
they have difficulty developing or implementing the strategy?
(13)
What
steps in the problem-solving procedure do the students have trouble with?
(14)
When
children have difficulties, do they lose their interest?
(15)
Can
we provide necessary hints and helps to foster their interest?
(16)
Do
we give them enough time to think?
(17)
Do
we foster the logical thinking students should use to solve the problems?
(18)
Do
we provide necessary tools for them to solve the problems?
(19)
Do
we ask them to use or find different methods to solve a problem?
(20)
Do
we ask them to compare different ways to solve the problem?
(21)
Do
we ask if they can use the same strategy to solve different problems?
(22)
Once
they master certain problems, what level of problems should they be given to
solve next?